Armstrong number or not in Java

import java.io.*;

class Armstrong{
      public static void main(String args[]){
try{
  BufferedReader object = new BufferedReader(new InputStreamReader(System.in));
  System.out.println("Enter number");
  int num= Integer.parseInt(object.readLine());
  int n = num; 
  int check=0,remainder;
  while(num > 0){
  remainder = num % 10;
  check = check + (int)Math.pow(remainder,3);
  num = num / 10;
  }
  if(check == n)
  System.out.println(n+" is an Armstrong Number");
  else
  System.out.println(n+" is not a Armstrong Number");
}
  catch(Exception e){
  System.out.println("Out of range!");
  }
   }
}

Example :

Input – 153

Output - 153 is Armstrong Number

Posted in: Code Snippet